Explanation : Push ‘r’ consist of following operations :
M[SP ]!R
SP!SP-1
‘r’ is stored at memory at address stack pointer
currently is, this take 2 clock cycles
SP is then decremented to point to next top of
stack
Explanation : In a line, there can be three possibilities : 1. Stuck-at 0 fault 2. Stuck-at 1 fault 3. No fault Thus, total combinations = 3N It is mentioned that one or more lines have stuck at faults. So, a case in which there is no fault in any line i.e. all lines are correct can not occur. Total combinations = 3N – 1