CTET Solved Paper MCQ - UTET April 2015 Paper2

101 In a right triangle, the square of hypotenuse is equal to twice the product of remaining two sides. If the base of this triangle is 12 cm, then the perpendicular of triangle will be

Given condition is,
h² = 2 (6 × p)
⇒ h² = 2 (12 × p) (Here, p = Perpendicular)
We know that,
h² = b² + p²
⇒ h² = 144 + p²
⇒ 24p = 144 + p²
⇒ p² -24p + 144 = 0
⇒ p² - 12p - 12p + 144 = 0
⇒ p(p - 12)-12(p - 12) = 0
Solving above equation, we get, p = 12
So, the perpendicular of triangle will be 12 cm

102 If the sum of five successive integers are S, then the value of largest integer in terms of S will be

Let five consecutive integers are (n - 4), (n - 3), (n - 2), (n - 1), n
According to question,
S = n - 4 + n -3 + n - 2 + n - 1 + n [n = Largest integer]
S = 5n - 10
S + 10 = 5n
n = (S + 10) / 5

103 In a sports competition, 5 players are participating. It is compulsory for each player to play match with every other player. How many matches will be played?

Total number of players = 5 and it is compulsory for each player to play match with every other player.
So, number of matches = ³C₂

104 In the given figure, both ABCD and PQRS are the parallelograms. The value of θ will be

From the figure, AD ∥ BC

So, ∠ADC = ∠BCR = 120⁰ [corresponding angles]
∴ ∠BCS = 180⁰ - 120⁰ = 60⁰
Similarly, SP ∥ RQ
∠RQP = ∠SPB = 70⁰ [corresponding angles]
Now, DC ∥ AP and SP is a transversal
∴ ∠RSP = 70⁰ [alternate angles]
In △OSC,
∠OSC + ∠SCO + ∠COS = 180⁰
⇒ 70⁰ + 60⁰ + ∠COS = 180⁰
⇒ ∠COS = θ = 50⁰

105 Which of the following options does not demonstrate the achievement of skill objectives of teaching, school mathematics in upper primary stages?

Solving a routine type of problem using a formula does not demonstrate the achievement of skill objectives of teaching school mathematics in upper primary stages