When A runs 5 rounds, B runs 4 rounds (ratio of speeds)
A passes B each time A has run 5 rounds or 5 x 1/4 = 5/4km. = 1 1/4km
1 1/4km is contained in 4 km 3 times. Hence A passes B thrice.
A passes B each time A has run 5 rounds or 5 x 1/4 = 5/4km. = 1 1/4km
1 1/4km is contained in 4 km 3 times. Hence A passes B thrice.


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⇒ (5)6 + (5 - x)4 + (5 - 2x)3 = 60
⇒ 30 + 20 - 4x + 15 - 6x = 60
⇒ x =