- Option : A
- Explanation : Given, A/B= 2/3 , B/C = 4/5 , C/D = 5/8 A/D = A/B × B/C × C/D = 2/3 × 4/5 × 5/8 = 1/3

- Option : D
- Explanation : Let the addition of two sums be x . First sum = 48 ∴ 8/ (8+13) × x = 48 ⇒ (8/21) x = 48 ⇒ x = 126 INR

4. If a/b = b/c = c/d, then (b^{3} + c^{3} + d^{3} ) / (a^{3} + b^{3} + c^{3} ) will be equal to

- Option : D
- Explanation : Let a/b = b/c = c/d =k.

⇒ a=bk=ck^{2}=dk^{3}, b=dk^{2}and c=dk.

(b^{3}+ c^{3}+ d^{3}) / (a^{3}+ b^{3}+ c^{3}) = [(dk^{2})^{3}+ (dk)^{3}+ d^{3}]/ [(dk^{3})^{3}+ (dk^{2})^{3}+ (dk)^{3}]

=d^{3}[ K^{6}+ K^{3}+1] / d^{3}[K^{9}+ K^{6}+ K^{3}]

=[ K^{6}+ K^{3}+1]/K^{3}[ K^{6}+ K^{3}+1]

=1/K^{3}=1/a/d =d/a

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