December 2015 - Paper 3

11:  

A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network ?

A.

2 Mbps

B.

60 Mbps

C.

120 Mbps

D.

10 Mbps

 
 

Option: A

Explanation :

In data transmission, throughput is the amount of data moved successfully from one place to another in a given period of time, and typically measured in bits per second (bps), or in megabits per second (Mbps) or gigabits per second (Gbps).
 
Here, Throughput = 15000 x 8000/60 = 2 Mbps

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12:  

Consider a subnet with 720 routers. If a three-level hierarchy is choosen with eight clusters, each containing 9 regions of 10 routers, then total number of entries in the routing table is ...................

A.

25

B.

27

C.

53

D.

72

 
 

Option: A

Explanation :

Each router needs 10 entries for local routers, 8 entries for routing to other regions within its own cluster, and 7 entries for distant clusters, for a total of 25 entries.

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13:   In a classful addressing, the IP addresses with 0 (zero) as network number:
A.

refers to the current network

B.

refers to broadcast on the local network

C.

refers to broadcast on a distant network

D.

refers to loopback testing

 
 

Option: B

Explanation :

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14:  

In electronic mail, which of the following protocols allows the transfer of multimedia messages?

A.

IMAP

B.

SMTP

C.

POP 3

D.

MIME

 
 

Option: D

Explanation :

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15:  

A device is sending out data at the rate of 2000 bps. How long does it take to send a file of 1,00,000 characters ?

A.

50

B.

200

C.

400

D.

800

 
 

Option: C

Explanation :

1,00,000 characters = 1,00,000 x 8 bits = 8,00,000 bits
8,00,000 bits/2000 bps = 400 seconds

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