JUNE 2013 - Paper 2

Match the following:

a. Good quality i. Program does not fail for a

specified time in a given
environment'

b. Correctness ii. Meets the functional

requirements

c. Predictable iii. Meets both functional and

non-functional requirements ,

d. Reliable iv. Process is under statistical

control

Codes

a b c d

A.	iii ii iv i
B.	ii iii iv i
C.	i ii iv iii
D.	i ii iii iv
	Answer Report Discuss
	Option: B Explanation : "Quality" should be used as a measure of functional/aesthetic utility to our consumer, and not as a measure of defects. Really, it should just be assumed that defects are generally absent. This should just be implied in what it means to be a Professional. So answer is 'B Click on Discuss to view users comments. Write your comments here: Updating your Comments.. Updating your Comments..

When the following code is executed , what will be the value of x and y ?

int x =1, y= 0;

y=x++;

A.	2,1
B.	2,2
C.	1,1
D.	1,2
	Answer Report Discuss
	Option: A Explanation : Here y will be assigned with value of x first and after that x will be incremented. So x=2 and y=1 Click on Discuss to view users comments. Sanjeev said: (7:47pm on Tuesday 3rd December 2013) answer should be A - 2,1FROM THE BOOK C LANGUAGE - Kernihan and Ritchie------C provides two unusual operators for incrementing and decrementing variables. The increment operator adds 1 to its operand, while the decrement operator -- subtracts 1. We have frequently used to increment variables, as in if (c == '\\n') nl; The unusual aspect is that and -- may be used either as prefix operators (before the variable, as in n), or postfix operators (after the variable: n ). In both cases, the effect is to increment n. But the expression n increments n before its value is used, while n increments n after its value has been used. This means that in a context where the value is being used, not just the effect, n and n are different. If n is 5, then x = n ; sets x to 5, but x = n; 44 sets x to 6. In both cases, n becomes 6. Write your comments here: Updating your Comments.. Updating your Comments..

In substitution, a character in the plaintext is always changed to the same character in the ciphertext, regardless of its position in the text

A.	polyalphabetic
B.	mono alphabetic
C.	transpositional
D.	multialphabetic
	Answer Report Discuss
	Option: B Explanation : In Symmetric-Key Cryptography , we use two main approaches: • Substitution ciphers • Transposition Ciphers Substitution ciphers is of 2 types Mono-alphabetic: In mono-alphabetic substitution, a character in the plaintext is always changed to the same character in the cipertext regardless of its position in the text. Example: If character ‘A’ in the plaintext must be changed to character ‘D’, every character ‘A’ is changed to character ‘D’, regardless of its position in the text Poly-alphabetic: In poly-alphabetic substitution, each occurrence of a character can have a different substitute. The relationship between a character in the plaintext to a character in the ciphertext is one-to-many. Example: Character ‘A’ can be changed to ‘D’ in the beginning of the text, but it could be changed to ‘N’ at the middle. Click on Discuss to view users comments. Write your comments here: Updating your Comments.. Updating your Comments..

The equivalent productidn rules corresponding to the production rules

S → Sα₁ | Sα₂ | β₁ | β₂

A.	S → β₁ \| β₂ A → α₁A \| α₂ A \| λ
B.	S → β₁ \| β₂ \| β₁ A \| β₂ A A → α₁A \| α₂ A
C.	S → β₁ \| β₂ A → α₁A \| α₂ A
D.	S → β₁ \| β₂ \| β₁A \| β₂A A → α₁A \| α₂ A \| λ
	Answer Report Discuss
	Option: D Explanation : S --> S+S \| SS \| S\|a \| (S) --------------------- S α form β form Left-Recursive-Rules Non-Left-Recursive-Rules We can write like S ---> Sα1 \| Sα2 \| Sα3 \| β1 \| β2 Rules to convert in equivalent Non-recursive grammar: S ---> β1 \| β2 Z ---> α1 \| α2 \| α3 Z ---> α1Z \| α2Z \| α3Z S ---> β1Z \| β2Z Click on Discuss to view users comments.* komal said: (11:26am on Tuesday 24th September 2013) as in option d,a tends to lemda then after putting lemda we get equivalent ans as given by s, in option b,a does not contain lemdaso it give beta1 alpha1 A which is not similar to s Write your comments here: Updating your Comments.. Updating your Comments.. → Sα₁ \| Sα₂ \| β₁ \| β₂ '>

Using data p=3, q=11, n=pq, d=7 in RSA algorithm find the cipher text of the given plain text SUZANNE

A.	BUTAEEZ
B.	SUZANNE
C.	XYZABCD
D.	ABCDXYZ
	Answer Report Discuss
	Option: A Explanation : Encryption RSA algorithm Cipher text = ((plaintext)^e)mod n From the given problem we know p =3,q = 11, d =7, n=33 find z :: z = ((p-1)(q-1)) => 210 = 20 Find 'e' or 'd' using the given method : (de) mod z = 1 Therefore (7e)mod 20 = 1 => with trail and error giving e =3, => (73)mod 20 = Finding e=3 we go to the encryption by converting the given plain text equivalent number starting a=1,b=2...z=26 Therefore SUZANNE = 19,21,26,1,14,14,5 taking single character and apply encryption (19^3) mod 33 = 28 ie (28-26) = 2 => B (21^3) mod 33 = 21=> U (26^3)mod 33 = 20=> T (1^3)mod 33 = 1=> A (14^3)mod 33 = 5=>E (5^3)mod 33 = 26 => Z Click on Discuss to view users comments.* Write your comments here: Updating your Comments.. Updating your Comments..

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