Let’s assume Z = 2, then gantt chart will be,
Average waiting time,
= {(4-0-3) + (2-1-1) + (9-3-3) + (6-4-2)} / 4
= (1 + 0 + 3 + 0) / 4
= 4 / 4
= 1
So, answer is 2.
| P1 | P2 | P1 | P1 | P4 | P3 | |
| 0 | 1 | 2 | 3 | 4 | 6 | 9 |


Total number of items in the set GOTO
(I0, 〈 ) is 5.
= 1.2.3.2 = 12
= 160 x 106