PREVIOUS YEAR SOLVED PAPERS MCQ - GATE 2019

Correct AnswerOption A
Rate difficulty Rate difficulty:
Choose a difficulty.
Share this question
Share:

No. of pairs with path length 0=8.0=8.
No. of pairs with path length 1=0.1=0.
No. of pairs with path length 2=8.2=8.
No. of pairs with path length 3=0.3=0.
No. of pairs with path length 4=16.4=16.
No. of pairs with path length 5=0.5=0.
No. of pairs with path length 6=32.6=32.
Total number of possible pairs =8×8=64=8×8=64
So, expected path length,E(x),
=0×864+2×864+4×1664+6×3264=27264=4.25
Cancel reply

Your email address will not be published. Required fields are marked *


Cancel reply

Your email address will not be published. Required fields are marked *

Correct AnswerOption A
Rate difficulty Rate difficulty:
Choose a difficulty.

It is given that, Polynomial 3x2 + 6xY + 3Y + 6 has only real roots
b2 – 4ax ≥ 0
(6Y)2 – 4(3) (3Y+ 6) ≥ 0
Y2 – Y - 2 ≥ 0<
>Y ∈ (–∞, – 1] ∩ [2, ∞)
⇒ Y ∈ [2, 6)
Since y is uniformly distributed in (1, 6)
Probability distributed function,
Gate2019 cs
Cancel reply

Your email address will not be published. Required fields are marked *


Cancel reply

Your email address will not be published. Required fields are marked *

Correct AnswerOption A
Rate difficulty Rate difficulty:
Choose a difficulty.

The DFA for accepting L will have 5! = 120 states, since we need one state for every possible permutation function on 5 elements. The starting state will be “id” state, named as Gate2017 cs and from there
n! arrows will go the n! states each named with a distinct permutation of the set {1, 2, 3, 4, 5}. Since composition of permutation function is closed every arrow has to go to some permutation and hence some state.
Since the language only has those strings where π(x) = id only the starting state (“id” state) will be the final state. Sample machine with only 2 states is shown below
Gate2017 cs
Cancel reply

Your email address will not be published. Required fields are marked *


Cancel reply

Your email address will not be published. Required fields are marked *

Correct AnswerOption A
Rate difficulty Rate difficulty:
Choose a difficulty.

If a switch has 8 ports then it means it can connect maximum 8 host. and 2 switch can connect 16 hosts independently. but we need one port for both of them to connect with each other. so now one- one port is used from both the switches for connecting then total port available free on both the switch is 7. so maximum 14 host can be connected but for the 15th host we need another switch.
3 switches of ethernet are required to connect 15 computers.
Hence, 3 is correct answer.
Cancel reply

Your email address will not be published. Required fields are marked *


Cancel reply

Your email address will not be published. Required fields are marked *

Correct AnswerOption A
Rate difficulty Rate difficulty:
Choose a difficulty.
Found this useful?
Follow:

f = Σm(0, 2, 5, 7, 8, 10, 13, 15)
f = ΠM(1, 3, 4, 6, 9, 11, 12, 14)
Gate 2019cs
f can be implemented using 3 NOR gates.
So, option (A) is correct
Cancel reply

Your email address will not be published. Required fields are marked *


Cancel reply

Your email address will not be published. Required fields are marked *

Why Practice with Avatto?
High Quality MCQsExam-focused questions with accurate answers
Detailed ExplanationsStep-by-step explanations to enhance learning
Latest Exam PatternBased on updated syllabus and pattern
Performance AnalyticsTrack performance and improve weak areas
100% Free PracticePractice unlimited questions for free
Boost Your PreparationAttempt mock tests, previous year papers and topic-wise quizzes.Explore All Tests →