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CTET Solved Paper MCQ - CTET September 2016 Paper2

41 If one angle of a triangle is 110°, then the angle between the bisectors of the other two angles measures

Let the ΔABC, in which AM and CN are angle bisectors.
∠A + ∠B + ∠C =180°
⇒ ∠A + 110° + ∠C = 180°
⇒ ∠A + ∠C=180-110°
⇒ ∠A/2 + ∠C/2 = 70°/2
⇒ ∠A/2 + ∠C/2 = 35 ... (i)
Now the angle bisectors meet at O.
In ΔAOC,
∠A/2 + ∠C/2 + ∠AOC =180°
=> 35° + ∠AOC = 180° [From Eq. (i)]
⇒ ∠AOC = 180° - 35°
∠AOC = 145°

42 In ΔABC, AB=4cm, AC=5cm and BC=6cm. In ΔPQR, PR=4cm, PQ=5cm and RQ=6cm. ΔABC is congruent to

ΔABC ≈ ΔPRQ

43 A tank is in the form of a cuboid. It holds a maximum of 540 m³ water. If the tank is 8 m long and 15 m wide, then how many metres deep must the water be when the tank is 2/3 full?

Volume of a cuboid (tank)=lxbxh
⇒ 540 m³ = 8 x 15 x h
⇒ Height of the tank = 540/8x15
= 4.5 m
Now, water height in the tank = 2/3 of tank height = 2/3 x 4.5 = 3 m

44 The ratio of the areas of two equilateral triangles is 16:9. If the perimeter of the smaller triangle is 63cm, then how much larger is a side of the larger triangle than a side of the smaller triangle?

CTET paper2

45 The area of a triangle is equal to the area of a circle whose perimeter is 6Π cm. If the base of the triangle is 8cm, then its corresponding height (in cm) is

Perimeter of circle = 2Πr
⇒6Π = 2Πr r - 3cm
Area of circle= Πr² = Π(3)²
=9Π cm² ....(i)
Since Area of Triangle = Area of a circle (given)
⇒ 1/2 x base x height = 9Π
(put the value of Eq(i) i.e., A=9Π)
⇒ 1/2 x 8 x h=9Π
⇒ h=9Π x 2/8
⇒ h=9/4 Π
⇒ h=2.25Π

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Question:

लेखक ने शिक्षा के सन्दर्भ में किस बात को महत्व दिया है?

A. शिक्षा को
B. विवेक को
C. बाजार को
D. साधना को

Correct answer: A

Explanation:

लेखक ने शिक्षा के सन्दर्भ में दो रस्ते बताए हैं- एक रास्ता चकाचौंध का जबकि दूसरा साधना का मार्ग| दूसरा मार्ग हमें शान्ति, सन्तोष तथा विवेक दे सकता…

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