The skill(s) developed in the students through this activity are observation, experimentation, and creativity.
CTET Solved Paper MCQ - CTET Feburary 2016 Paper2
Given, each angle of regular polygon = 108°
We know,
Angle of regular polygon = 180° - 360°/n
∴ 180° - 360°/n = 108°
∴ 180°n - 360° = 108°n
⇒ 180°n - 108°n = 360°
⇒ 72°n = 360°
⇒ n = 360°/72° = 5.
∴ Number of sides of the givcn polygon =5.
We know,
Angle of regular polygon = 180° - 360°/n
∴ 180° - 360°/n = 108°
∴ 180°n - 360° = 108°n
⇒ 180°n - 108°n = 360°
⇒ 72°n = 360°
⇒ n = 360°/72° = 5.
∴ Number of sides of the givcn polygon =5.
∴ Here, BD divides quadrilateral in two triangles.
Now,
Area of ΔABD = 1/2 x BD x AM
⇒ 1/2 x 40 x 16 = 320cm2
Area of ΔBCD = 1/2 x BD x NC
⇒ 1/2 x 40 x 16 = 240cm2
∴ Area of quadrilateral
ABCD = 320 + 240 = 560 cm2.

