Diameter of semi-circle = 49cm
Perimeter = πr+d
= 22/7 × 49/2 + 49
= 77 + 49 = 126 cm
Perimeter = πr+d
= 22/7 × 49/2 + 49
= 77 + 49 = 126 cm
CTET Maths MCQ - Geometry & Mensuration
Here, ∠ACD = 400 + x0
[exterior angle theorem]
and y0 + ∠ACD + 400 = 1800
⇒ y0 + 400 + x0 + 400 = 1800
⇒ x0 + y0 = 1800 - 800 = 1000
[exterior angle theorem]
and y0 + ∠ACD + 400 = 1800
⇒ y0 + 400 + x0 + 400 = 1800
⇒ x0 + y0 = 1800 - 800 = 1000
Area of PQRS = 20 × 20
= 400 sq cm
Area of ΔTSU = 1/2 × 10 × 10
=50 sq cm
Area of ΔQUR = 1/2 × 10 × 20
=100 sq cm
And area of ΔPTQ = 1/2 × 10 × 20
=100 sq cm
∴ Area of shaded region = 400 - (50 + 100 + 100)
= 150 sq cm
= 400 sq cm
Area of ΔTSU = 1/2 × 10 × 10
=50 sq cm
Area of ΔQUR = 1/2 × 10 × 20
=100 sq cm
And area of ΔPTQ = 1/2 × 10 × 20
=100 sq cm
∴ Area of shaded region = 400 - (50 + 100 + 100)
= 150 sq cm
