CTET Maths MCQ - Algebra
at 10% per annum,
compounded yearly.
Here, P = 8000 Rs, x = 20 Rs.
p= x(100/r)2
⇒8000 = 20(100/r)2
400 = 1002 /r2 .
r2 = (100 x 100)/400 = 25.
r = 5% per annum
p= x(100/r)2
⇒8000 = 20(100/r)2
400 = 1002 /r2 .
r2 = (100 x 100)/400 = 25.
r = 5% per annum
Let purchase price be x Rs.
Price after 1 year,
x-(10/100) × x=9x/10.
Price after II year,
(9x/10) - (10/100) × (9x/10) =81x/100.
According to the question,
81x/100 = 24300.
x=(24300 × 100)/81
x= 30000 Rs
Price after 1 year,
x-(10/100) × x=9x/10.
Price after II year,
(9x/10) - (10/100) × (9x/10) =81x/100.
According to the question,
81x/100 = 24300.
x=(24300 × 100)/81
x= 30000 Rs
