# Theory Of Computation MCQ - Regular languages and finite automata

1:

Number of states of the FSM required to simulate behaviour of a computer with a memory capable of storing "m" words, each of length 'n'

 A. m x 2n B. 2mn C. 2m+n D. all of these Answer Report Discuss Option: B Explanation : For every data here length is ‘n’ and memory's states are defined in terms of power of 2,  Here the total memory capability for all the words = mn Hence number of states are 2mn Click on Discuss to view users comments. vikki gound said: (1:06am on Thursday 23rd May 2013) total length m nso required memory=2^m n Write your comments here:
2:

An FSM with

 A. 1 stack is more powerful than an FSM with no stack B. 2 stacks is more powerful than a FSM with 1 stack C. both (a) and (b) D. None of these Answer Report Discuss Option: C Explanation : Click on Discuss to view users comments. Write your comments here:
3:

If two finite states machine M and N are isomorphic, then

 A. M can be transformed to N, merely re-labelling its states B. M can be transformed to N, merely re-labelling its edges C. Both (a) and (b) D. None of these Answer Report Discuss Option: A Explanation : Click on Discuss to view users comments. Write your comments here:
4:

Power of

 A. DFSM and NDFSM are same B. DFSM and NDFSM are different C. DPDM and NDPDM are diferent D. Both (A) and (C) Answer Report Discuss Option: D Explanation : Click on Discuss to view users comments. Aman said: (10:52am on Wednesday 26th July 2017) Because there is an algorithm to convert DFSM to NDFSM and there may or may not be possible DPDM for every NDPDM so both are different Write your comments here:
5:

Which of the folowing pairs of regular expressions are equivalent ?

 A. 1 (01)* and (10)* 1 B. x (xx) * and (xx) * x C. x+ and x+x*+ D. All of these Answer Report Discuss Option: D Explanation : Option (a) and option (b) are similar deriving expressions using rule :-  (pq)*p = p(qp)* Option (c) will also be valid since:- (x+x*+) will be --->(xx*)(x*x**) --->(xx*)(x*x*)                                (Using x** = x*) --->(xx*)(x*)                     (Using x*x* = x*) --->(xx*)                              (Using x*x* = x*) --->x+ So, the answer will be all of these (Option d) Click on Discuss to view users comments. Naween said: (8:32pm on Thursday 16th May 2013) I think this ans is wrong as all are true as we expand each and every one all seems are true Mrugesh said: (5:02pm on Wednesday 28th August 2013) As property(PQ)*P = P(QP)* option A and B are also correct... So answer should be D !!! taraka said: (12:16pm on Thursday 12th September 2013) from the identity rules (PQ)*P=P(QP)* So option A and B also correct so final Option is D. Write your comments here:

Syllabus covered in this section is-

• Regular languages and finite automata
• Context free languages and Push-down automata
• Recursively enumerable sets and Turing machines
• Undecidability, NPcompleteness
• Models of computation-Finite Automata
• Pushdown Automata
• Non-detenninism and NFA. DPDA and PDAs and Languages accepted by these Structures
• Grammars, Languages,
• Non- computability and Examples of non-computable problems

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