Mathematical Aptitude MCQ - Interest
Therefore, principal = Rs (1008 – 208) = Rs 800.
Now, P = 800, T= 2 and S.I. = 208.
Therefore, rate = (100 × S.I.)/(P × T) = [(100 × 208)/(800 × 2)]% = 13%
Let the sum be Rs a.
Then we can write: [{x × 10 × 7}/{100 × 2}] – [{x × 12 × 5}/{100 × 2}] = 40. This can be written as:
7x/20 – 3x/10 = 40.
Therefore, we have x = Rs 800.
Then we can write: [{x × 10 × 7}/{100 × 2}] – [{x × 12 × 5}/{100 × 2}] = 40. This can be written as:
7x/20 – 3x/10 = 40.
Therefore, we have x = Rs 800.
Here, we have, the principal = Rs [{100 × 5400}/{12 ×
3}] = Rs 15000.
Thus, the correct option is (D).
Thus, the correct option is (D).
