Statistics And Methodology MCQ - Statistics And Methodology Section 1
42
t is
N = 15, r = 0.6
Z = 1.1513 log 1 + r/1 - r
= 1.1513 log 1 + 0.6/1 - 0.6
= 1.1513 log 4
= 1.1513 x 0.6021
= 0.6932
S.E.2 = 1/√(N - 3) = 1√(15 - 3)
= 1√12 = 1/3.464 = 0.29
Z/(S.E.)2 = 0.6932/0.29 =2.39 > 1.96
Hence 'r' is significant at a 5% level of significance.
The answer is (c).
Total number of cases that can happen
= 52
No. of favorable cases = No. of queens in a pack
or 52= 4
The probability (P) will be -
P = 4/52 = 13
Hence the answer is (b).


