Explanation : Given IP addresses are of Class C
default Mask for class C = 24
The given mask is 11 bits 11111111 11111111 11111111 11100000
subnet ID: 3 bits
existing subnets: 011, 010 and 100
Explanation : For ip address 192.168.1.110/28
For network address keep Network bits as it is
and put host bits =0 in any given IP address.
Network address
= 192.168.1.01100000 ⟶ 192.168.1.96
For: 192.168.1.97/28
Network address
= 192.168.1.01100000 ⟶ 192.168.1.96
Explanation : Given : 10.105.1.113 and 10.105.1.91
When these are in same network, then AND with
netmask give the address of same ID otherwise
these are in different class in these only AND with
255.255.255.224 are in different class
This is 96 and 64. Then these are different ID
means 10.105.1.96 and 10.105.1.64 are different
ID. So this is not in same network.
When we do the similar operation with 2nd IP,
it gives 10.105.1.64
Here, it gives different IP
but for the rest it gives same IP.