Functions of OSI and TCP/IP Layers Q.22

  • Option : B
  • Explanation : For ip address 192.168.1.110/28
    For network address keep Network bits as it is and put host bits =0 in any given IP address.
    Network address
    = 192.168.1.01100000 ⟶ 192.168.1.96
    For: 192.168.1.97/28
    Network address
    = 192.168.1.01100000 ⟶ 192.168.1.96
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