Data Communication and Computer Networks - Functions of OSI and TCP/IP Layers
11. Which one of the following statements is FALSE?
- A
Packet switching leads to better utilization of bandwidth resources than circuit switching
- B
Packet switching results in less variation in delay than circuit switching
- C
Packet switching requires more per-packet processing than circuit switching
- D
Packet switching can lead to reordering unlike in circuit switching
- Option : B
- Explanation : False. Packet switching results in less variation in delay than circuit switching.
- Option : D
- Explanation : Subnet mask 255.255.31.0 shows class C network
So, class C network. IP address is
191.203.31.87 and 191.234.31.88
- Option : C
- Explanation : Network Address = IP address BITWISE AND
Subnet Mask
128.8.129.43 BITWISE-AND 255.255.31.0
= 128.8.1.0
128.8.161.55 BITWISE-AND 255.255.31.0
= 128.8.1.0.
- Option : A
- Explanation : For 1st packet,
128.75.43.16 BITWISE-AND 255.255.255.0
= 128.75.43.0
128.75.43.16 BITWISE-AND 255.255.255.128
= 128.75.43.0
Now, since both these subnet masks are producing the same Network ID, hence The one with greater number of ones will be selected, and the packet will be forwarded there. Hence packet 1 will be forwarded to Eth1.
For 2nd packet,
192.12.17.10 BITWISE-AND 255.255.255.0
= 192.12.17.0
{Does not match with any of the network addresses}
192.12.17.10 BITWISE-AND 255.255.255.128
= 192.12.17.0
{Does not match with any of the network addresses}
192.12.17.10 BITWISE-AND 255.255.255.255
=192.12.17.10
{Does not match with any of the network addresses}
Hence, default interface must be selected for packet 2, i.e Interface Eth2.
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