Data Communication and Computer Networks MCQ - Data Communication
The probability of success (i.e. exactly one frame in a slot) = 1 / e  ~ 0.368.
Then probability of a failure (no frames or multiple frames) = 0.632.
Thus joint probabilities of the two uplink channels are :
success on 1 and success on 2 : 0.135 (2 frames sent)
success on 1 and failure on 2 : 0.233 (1 frame sent)
failure on 1 and success on 2 : 0.233 (1 frame sent)
failure on 1 and success on 2 : 0.399 (0 frames sent)
Then expected number of success per slot.
E = 0.35 * x + 0.233 * 1 + 0.233 * 1 + 0.399 * 0 = 0.270 + 0.233 + 0.233 = 0.736Â
Then probability of a failure (no frames or multiple frames) = 0.632.
Thus joint probabilities of the two uplink channels are :
success on 1 and success on 2 : 0.135 (2 frames sent)
success on 1 and failure on 2 : 0.233 (1 frame sent)
failure on 1 and success on 2 : 0.233 (1 frame sent)
failure on 1 and success on 2 : 0.399 (0 frames sent)
Then expected number of success per slot.
E = 0.35 * x + 0.233 * 1 + 0.233 * 1 + 0.399 * 0 = 0.270 + 0.233 + 0.233 = 0.736Â
In time division switches 2nT = 1 frame period, where T = memory access time.
A bridge operates at the data link layer, giving it access to the physical address of all stations connected to it. Answer is physical addresses.
