Avatto > UGC NET COMPUTER SCIENCE > PRACTICE QUESTIONS > Data Communication and Computer Networks > Data Communication

Data Communication and Computer Networks MCQ - Data Communication

76 Phase shift keying (PSK.) method is used to modulate digital signals at 9600 bps using 16 levels. The line signals speed (i.e. modulation rate) will be

9600 corresponds to bits per second and the level is 16. For a 16-PSK, given the baud rate N, the bit rate would be 4N. Here bps is provided which is 9600.
In order to calculate the baud rate we have to divide bps/4, because the signal level is 16.So the answer would be 9600/4=2400 baud. Option is (A).

77 Television channels are 6 MHz. How many bits can be sent if four level digital signals are used (assume a noiseless channel)?

78 What is the maximum burst length on an 155.52 Mbps ATM ABR connection whose PCR value 200,000 and whose L value is 25 msec ?

Given : T = 5 μ sec
L = 25 μ sec
d = 2.73 μ sec.
N = (1 + L) / (T - δ) = 12.01 i.e. 12 cells.

79 Poll/select line discipline requires what to identify the packet recipient ?

In Poll / select method, every device on a link has an address that can be used for identification

80 In sliding window flow control, if window size is 63, what is the range of sequence numbers ?

In sliding window flow control the window size is 63, the range of sequence numbers are 0 to 63 { 0.....63}.

Your Progress

0%

Start Practising!

You've answered 0 of 98 questions in this topic.

Practice Spotlight

Build momentum in Data Communication

Start with a short question set, review every explanation, and revisit difficult questions before moving ahead.

Day 4 / 10

Global Spotlight

Build Your First Streak

Complete one short Data Communication session today, then return tomorrow. Consistency matters more than a long first session.

Day 7 / 10

Question Spotlight

Question:

The monitor station in what standard ensures that one and only one token is circulating ?

A. 802.3
B. 802.5
C. Both (a) and (b)
D. All of these

Correct answer: B

Explanation:

Here 802.3 is Ethernet, it uses CSMA/CD. But 802.5 is Token ring. It will have only one token in circulation. These are IEEE standards but FDDI is ANSI…

Click to view the complete question details

Day 4 / 10 Open this question

Community Insight

Based on 73 saved attempts

Most Attempted TopicCloud Computing
Most Challenging TopicCloud Computing
Average Accuracy97%

Featured Question

(Based on recent community answers)

Q. #263730% Incorrect

Which of the following is possible in a token passing bus network ?

Try This Question →

This Week's Challenge

Complete 20 questions and set the community benchmark!

0 / 20 Start Challenge →

Why Practice with Avatto?

High Quality MCQsExam-focused questions with accurate answers

Detailed ExplanationsStep-by-step explanations to enhance learning

Latest Exam PatternBased on updated syllabus and pattern

Performance AnalyticsTrack performance and improve weak areas

100% Free PracticePractice unlimited questions for free

Forgot your password?

I agree with the Terms.