Data Communication and Computer Networks - Data Communication
- Option : A
- Explanation : 9600 corresponds to bits per second and the level is 16. For a 16-PSK, given the baud rate N, the bit rate would be 4N. Here bps is provided which is 9600.
In order to calculate the baud rate we have to divide bps/4, because the signal level is 16.So the answer would be 9600/4=2400 baud. Option is (A).
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- Option : A
- Explanation :
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- Option : B
- Explanation : Given : T = 5 μ sec
L = 25 μ sec
d = 2.73 μ sec.
N = (1 + L) / (T - δ) = 12.01 i.e. 12 cells.
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79. Poll/select line discipline requires what to identify the packet recipient ?
- Option : C
- Explanation : In Poll / select method, every device on a link has an address that can be used for identification
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80. In sliding window flow control, if window size is 63, what is the range of sequence numbers ?
- Option : A
- Explanation : In sliding window flow control the window size is 63, the range of sequence numbers are 0 to 63 { 0.....63}.
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