Maths - General Airthmatic
- Option : C
- Explanation : Given, a < b a. b+c>c+a ... (i) and since c > a => c + a> a + b ... (ii) so b+c>c+a>a+b [from Eq. (i) and (ii)]. Hence (b + c)/(a+b+c) > (c + a)/(a+b+c) > (a + b)/(a+b+c)
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13. The average of 3 numbers is 7 and average of first two numbers is 4. What is the third number?
- Option : B
- Explanation : As, Total of three numbers
= 3 x 7 = 21
Total of first two numbers = 4 x 2 = 8
∴ Third number = 21 - 8 = 13.
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