Given, a < b a.
b+c>c+a ... (i)
and since c > a
=> c + a> a + b ... (ii)
so b+c>c+a>a+b
[from Eq. (i) and (ii)].
Hence (b + c)/(a+b+c) > (c + a)/(a+b+c) > (a + b)/(a+b+c)
Maths MCQ - General Airthmatic
is
As, Total of three numbers
= 3 x 7 = 21
Total of first two numbers = 4 x 2 = 8
∴ Third number = 21 - 8 = 13.
= 3 x 7 = 21
Total of first two numbers = 4 x 2 = 8
∴ Third number = 21 - 8 = 13.
