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Maths MCQ - Geometry

1 In the following figure, the value of x is

∠CBA =180° -65°=115°.

∠DCB =180° -80°=100°. ∠EDC=1I5°. ∠A =90°. ∠DEA =540°. - (115°+ 100° + 115° + 90°) =120°. [sum of all angles 'in a pentagon is 540°]. ∠x = 180° -120°=60°

2

reetfeb16/q96

As, we know that
∠AOC+ ∠BOC = 180° (Linear Pair)
⇒ 50° + ∠BOC = 180°
⇒ ∠BOC = 180° - 50°
= 130°

3

reetfeb16/q97

As, ∠ACB = 180° - (∠ABC+ ∠BAC)
= 180° - (50°+ 30°) = 100° (Sum of angles of a triangle)
∴ ∠ACD = 180° - 100° = 80° (Linear Pair)
∴ ∠AED = ∠ACD + ∠EDC
= 80° + 25° = 105° (Exterior Angle Theorem).

4 The sum oflength oftwo sides of a triangle is always

Sum of length of two sides of a triangle is always greater than the third side.

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A. 105°
B. 115°
C. 95°
D. 75°

Correct answer: A

Explanation:

As, ∠ACB = 180° - (∠ABC+ ∠BAC) = 180° - (50°+ 30°) = 100° (Sum of angles of a triangle)∴ ∠ACD = 180° - 100° = 80° (Linear…

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