Maths MCQ - Data Handling
The mean of n observation is m.
if m2 - m + 1 is added to cach observation, then the mean will increase by m2 - m + 1,
Then new mean = m + m2 - m + 1
= (1 + m2)
if m2 - m + 1 is added to cach observation, then the mean will increase by m2 - m + 1,
Then new mean = m + m2 - m + 1
= (1 + m2)
Arranging the numbers in ascending order, we get 6, 6, 8, 8, 9, 9, 9, 14
As, median is middle number and here 8 and 9 are middle numbers. So median = (8 + 9)/2 = 8.5
Mode is the number that appears the most, which is 9.
So, Mean of median and mode = (8.5 + 9)/2 = 17.5/2 = 8.75
As, median is middle number and here 8 and 9 are middle numbers. So median = (8 + 9)/2 = 8.5
Mode is the number that appears the most, which is 9.
So, Mean of median and mode = (8.5 + 9)/2 = 17.5/2 = 8.75
Sum of production during
odd years (2009, 2011, 2013)
= 90 + 105 + 75 = 270 tonne.
Sum of production during even years
(2010,2012,2014)
=110 + 130 + 120 = 360 tonne.
Let the sum of production during odd
years is x times that of the even years.
270 = x × 360 => x = 270/360.
x =0.75
odd years (2009, 2011, 2013)
= 90 + 105 + 75 = 270 tonne.
Sum of production during even years
(2010,2012,2014)
=110 + 130 + 120 = 360 tonne.
Let the sum of production during odd
years is x times that of the even years.
270 = x × 360 => x = 270/360.
x =0.75
