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Digital Logic MCQ - Number representations and computer arithmetic

6 A decimal number has 25 digits. The number of bits needed for its equivalent binary representation is, approximately

The largest decimal number with 25 digits is 9,999,999,999,999,999,999,999,999. The smallest decimal number in the form 2ⁿ-1 which is greater than or equal to that is 19,342,813,113,834,066,795,298,815. That corresponds to 2⁸⁴-1. So, the minimum number of binary bits required to represent the decimal number 25 nines in a row is 84. This is 84 ones in a row. If you want to support negative as well as positive numbers, you will need 85.

7 Decimal number 5 in level parity self correcting code is

8 The decimal number 80 can be represented in BCD code as

9

How many fractional digits 2^-48 will have?

10 The 10's complement of (715)₈ is

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Question:

The 10's complement of (715)8 is

A. 63
B. 539
C. 285
D. 395

Correct answer: B

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