CTET Solved Paper MCQ - UPTET Feburary 2014 Paper2
For 1. Given dimensions of cuboid arc 5 cm, 2 cm and 5 cm.
Here, LCM of 5 , 2 and 5 is 10.
5 x 2 = 10; 2 x 5 = 10; 5 x 2 = 10.
Hence, the minimum number of cuboids require to form a cube
= 2 x 5 x 2 = 20.
Since it has more than one correct answers, it is an open-ended problem.
For 2.
For 3.
10 = 2 x 5; Cube of 10 = (10)3 or (2 x 5)3.
Since it has more than one ways for finding cube so it is an open-ended problem.
For 4.
Numbers whose cube is more than 64 are 5,6,7,8,9.
Since it has more than one correct answers so it is also an open-ended problem.
Here, LCM of 5 , 2 and 5 is 10.
5 x 2 = 10; 2 x 5 = 10; 5 x 2 = 10.
Hence, the minimum number of cuboids require to form a cube
= 2 x 5 x 2 = 20.
Since it has more than one correct answers, it is an open-ended problem.
For 2.
For 3.
10 = 2 x 5; Cube of 10 = (10)3 or (2 x 5)3.
Since it has more than one ways for finding cube so it is an open-ended problem.
For 4.
Numbers whose cube is more than 64 are 5,6,7,8,9.
Since it has more than one correct answers so it is also an open-ended problem.
In ΔOAB, OA = OB (Radius of the circle)
∴ ∠OBA = ∠OAB = 40°
⇒ ∠AOB = 180° - ∠OAB - ∠OBA = l80° - 80°
i.e. ∠AOB =100°
⇒ ∠ACB = 1/2∠AOB [Degree measure theorem]
∠ACB=50°
∴ ∠OBA = ∠OAB = 40°
⇒ ∠AOB = 180° - ∠OAB - ∠OBA = l80° - 80°
i.e. ∠AOB =100°
⇒ ∠ACB = 1/2∠AOB [Degree measure theorem]
∠ACB=50°
