What is the minimum number of two-input NAND gates used to perform the function of two input OR gate ?
| A. | one |
| B. | two |
| C. | three |
| D. | four |
Answer : C Explanation : Y=A+B. This is the equation of OR gate. We require 3 NAND gates to create OR gate. We can also write
After 1st NAND operation So we need 3 NAND gates. meena vinay said: (12:45pm on Tuesday 21st April 2015)
the ouput after ist NAND and third NAND is same.So the answer is not correct
Gitanjali said: (1:43pm on Saturday 26th November 2016)
After first nand gate as well we are getting or answer .So the answer shd be after one nand gate
prathap said: (10:12pm on Wednesday 21st December 2016)
when we see the implementation of OR gate using NAND gate it is clearly saying that the minimum number of 2 input required are 3.
Shahroze Arslan said: (5:35am on Wednesday 9th May 2018)
a simple way to check this is through truth tableThe truth table of one OR gate (accepting two inputs minimum) and one NAND (accepting two inputs minimum) is same
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
