To make the following circuit a tautology ? marked box should be
| A. | OR gate |
| B. | AND gate |
| C. | NAND gate |
| D. | EX-OR GATE |
Answer : C Explanation : The output f = (x+x')+(y+y'). Starting derivation using 'f'. -->(x+x')+(y+y') -->(x+y)+(x'+y') -->(Already a known Input)+(x'+y') So, the unknown input is (x'+y'). This can be made by :- x and y fed into a NOT gate and then AND gate to become (x'+y'). So the answer is NAND gate. swetha k said: (5:02pm on Monday 5th October 2015)
it should be XOR isn't it??
Sachin Raj G.S said: (7:23pm on Wednesday 4th April 2018)
C is the exact answer for this question. 1st input is x y2nd input will be x' y'(nand gate)Next there is a and gate, so output should become,f=(x y).(x' y') =xx' xy' yx' yy' =1 xy' yx' 1 =1(because 1 a=1)
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
