(√2+√5)² = 2 + 2√10 +5 =7+2√10
(√7)² = 7
∴ √2+√5> 7
Alternatively:
√2 > √1 and √5 > √4
∴ √2+√5 > 2+1
=> √2 + √5 > 3 and √7 < √9 = 3
=> √7 < 3.
so √2 + √5>√7
(√7)² = 7
∴ √2+√5> 7
Alternatively:
√2 > √1 and √5 > √4
∴ √2+√5 > 2+1
=> √2 + √5 > 3 and √7 < √9 = 3
=> √7 < 3.
so √2 + √5>√7


