x2/yx + y2/zx + z2/xy
...(since, x+y+z=0 x3+y3+z3=3xyz)
(x3+y3+z3) / xyz = 3xyz / xyz = 3.
...(since, x+y+z=0 x3+y3+z3=3xyz)
(x3+y3+z3) / xyz = 3xyz / xyz = 3.
Since d = -2, maximum sum of the series will be sum of all the positive terms.
Least positive term of the series is 2 or 0 (both giving equal sum)
Let, 2 be the nth term
2 = 60 + (n 1) - 2
=> n = 30
Required sum = 30/2 (60 + 2) = 930
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