The sum 6 can be obtained as follows:
(1,5), (2, 4), (3, 3), (4, 2), (5, 1), i.e. in 5 ways.
Probability of A's throwing 6 with 2 dice = 5/36
Probability of A's not throwing 6 = 31/36
Similarly, probability of B's throwing 7 = 6/36, i.e. 1/6
Probability of B's not throwing 7 = 5/6
Now A can win, ifhe throws 6 in the first, third,
fifth, seventh etc. throws.
Chance of A's winning
(1,5), (2, 4), (3, 3), (4, 2), (5, 1), i.e. in 5 ways.
Probability of A's throwing 6 with 2 dice = 5/36
Probability of A's not throwing 6 = 31/36
Similarly, probability of B's throwing 7 = 6/36, i.e. 1/6
Probability of B's not throwing 7 = 5/6
Now A can win, ifhe throws 6 in the first, third,
fifth, seventh etc. throws.
Chance of A's winning
