Classical

Calculus - Calculus MCQ

11:  

 Minimum point of the function


is at

A.

x=1

B.

x=-1

C.

x=0

D.

x= 1/√3

 
 

Option: A

Explanation :

 => f'(x)= x2-1
 For maximum and minimum value, f'(x) = 0

∴ x2 -1= 0  x = ± 1
Again f(x) = 2x  At x = 1, f '(x) = 2 > 0  f '(x) = -2 < 0
Hence minimum at x = 1

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ishan said: (11:51am on Friday 30th September 2016)
how derivative of fx =x2 -1 while fx= x3/x=x2

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12:  



is equal to
 

A.

0

B.

C.

1

D.

-1

 
 

Option: A

Explanation :

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13:  

 If f (0) = 2 and f (x) = 1 /  (5-x2), then lower and upper bound of f(1) estimated by the mean value theorem are

A.

1.9,2.2

B.

2.2,2.25

C.

2.25,2.5

D.

None of these

 
 

Option: B

Explanation :

Calculus questions with explanation

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14:  

The unit normal to the plane 2x +y + 2z = 6 can be expressed in the vector form as

A.

i3 + j2 + k2

B.

Calculus questions

C.

Calculus mcq

D.

Calculus objective type questions

 
 

Option: B

Explanation :

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15:  

 Maxima and Minima occur

A.

simultaneously

B.

once

C.

alternately

D.

rarely

 
 

Option: C

Explanation :

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