Value of 'c' of the mean value theorem for the function f(x) = x(x - 2), when a = 0, b = 3/2, is
A. | 3/4 |
B. | 1/2 |
C. | 3/2 |
D. | 1/4 |
Option: A Explanation :
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If f(x , y) = x2 + y2, then ∇2 f is
A. | 4 |
B. | 2 |
C. | 0 |
D. | 4(x + y)2 |
Option: A Explanation :
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The value of integral
A. | 0 |
B. | 0.25 |
C. | 1 |
D. | ∞ |
Option: C Explanation :
Click on Discuss to view users comments. T. Singh said: (7:06am on Thursday 9th November 2017)
Option D should be correct as integral of 1/x2 is -1*(1/x) . Substitution of limits 2 and 0 will result as -1/2 infinity. So option D should be correct option.
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