UGC NET Paper1 Previous Year Solved Papers - 20th June 2019 Morning Shift
Consider the following table that shows the distribution of students in two sections A and B in a school according to the marks obtained by them. There is a total of 45 students in each of sections A and B. Answer the questions based on the data contained in the table:
Marks obtained by students
| Marks in Class Interval |
Number of students in | |
| Section A | Section B | |
| [0—9] | 2 | 4 |
| [10—19] | 5 | 5 |
| [20—29] | 10 | 9 |
| [30—39] | 4 | 4 |
| [40—49] | 8 | 7 |
| [50—59] | 4 | 5 |
| [60—69] | 7 | 5 |
| [70—79] | 5 | 6 |
31. How many students in Section A have obtained 30 or more marks but less than 50?
- Option : A
- Explanation : Number of students in section A have obtained
marks (30 - 39) = 4
(40-49) = 8
Number of students obtained between 30 to 50
= 4 + 8 = 12.
Consider the following table that shows the distribution of students in two sections A and B in a school according to the marks obtained by them. There is a total of 45 students in each of sections A and B. Answer the questions based on the data contained in the table:
Marks obtained by students
| Marks in Class Interval |
Number of students in | |
| Section A | Section B | |
| [0—9] | 2 | 4 |
| [10—19] | 5 | 5 |
| [20—29] | 10 | 9 |
| [30—39] | 4 | 4 |
| [40—49] | 8 | 7 |
| [50—59] | 4 | 5 |
| [60—69] | 7 | 5 |
| [70—79] | 5 | 6 |
- Option : B
- Explanation : Number of students in Section B have obtained more than 40 marks = 7 +5 + 5 + 6 = 23 Total number of students in Section B = 45 Percentage of students obtained more than 40 = 23/45 X 100 = 51.11% = 51%
Consider the following table that shows the distribution of students in two sections A and B in a school according to the marks obtained by them. There is a total of 45 students in each of sections A and B. Answer the questions based on the data contained in the table:
Marks obtained by students
| Marks in Class Interval |
Number of students in | |
| Section A | Section B | |
| [0—9] | 2 | 4 |
| [10—19] | 5 | 5 |
| [20—29] | 10 | 9 |
| [30—39] | 4 | 4 |
| [40—49] | 8 | 7 |
| [50—59] | 4 | 5 |
| [60—69] | 7 | 5 |
| [70—79] | 5 | 6 |
33. How many students in Section A and Section B together have obtained marks less than 10?
- Option : D
- Explanation : Number of students in Section A, obtained
less than 10 marks = 2
Number of students in Section B, obtained less than 10 marks = 4
Total number of students in both Section A and B obtained less than 10 marks = 2 + 4 = 6.
Consider the following table that shows the distribution of students in two sections A and B in a school according to the marks obtained by them. There is a total of 45 students in each of sections A and B. Answer the questions based on the data contained in the table:
Marks obtained by students
| Marks in Class Interval |
Number of students in | |
| Section A | Section B | |
| [0—9] | 2 | 4 |
| [10—19] | 5 | 5 |
| [20—29] | 10 | 9 |
| [30—39] | 4 | 4 |
| [40—49] | 8 | 7 |
| [50—59] | 4 | 5 |
| [60—69] | 7 | 5 |
| [70—79] | 5 | 6 |
34. If the pass mark is 30, what is the number of failures in both the sections together?
- Option : B
- Explanation : Number of students in Section A obtained
less than 30 marks = 2 + 5 + 10 = 17.
Number of students in Section B obtained less than 30 marks = 4 + 5 + 9 = 18.
Total number of failures in both Sections = 17+ 18 = 35.
Consider the following table that shows the distribution of students in two sections A and B in a school according to the marks obtained by them. There is a total of 45 students in each of sections A and B. Answer the questions based on the data contained in the table:
Marks obtained by students
| Marks in Class Interval |
Number of students in | |
| Section A | Section B | |
| [0—9] | 2 | 4 |
| [10—19] | 5 | 5 |
| [20—29] | 10 | 9 |
| [30—39] | 4 | 4 |
| [40—49] | 8 | 7 |
| [50—59] | 4 | 5 |
| [60—69] | 7 | 5 |
| [70—79] | 5 | 6 |
35. How many students in Section A and Section B have obtained 50 or more than 50 marks?
- Option : C
- Explanation : Number of students in Section A have
obtained more than 50 marks = 4 + 7 + 5 = 16.
Number of students in Section B have obtained more than 50 marks = 5 + 5 + 6 = 16.
Total number of students have obtained more than 50 marks in both Sections
= 16+ 16 = 32.
