Computer Graphics MCQ - Graphics Concepts
f(x) = x2 - |x| and f(x) =(x) (ax + 1) / (ax -1) are even functions, because
f(x) = f(-x).
f(x) = sin (x) + cos (x) is neither even nor odd as f(x) ≠f (-x) and - f(x) ≠f (-x)
For f(x) = x - [x]; where [x] stands for the greatest integer ≤ x,
solving the equation f(x + T) = f(x),
we get T = 1 as the period.
f(x) = |cos(x)| is periodic with period π
n.f(x) = (x)cos(x) and
f(x) = sin(1/x)
if x ≠0; 0 otherwise are not periodic.
