Explanation : Since the scalars are not all zero
ā“ The column vectors for i =1,2...,n are linearly dependent
ā |A| = 0 and ā Ax = b has infinitely many solutions.
Explanation : In the given questions
If lists are not NULL : Invocation of join will append list m to the end of list n if the lists are not NULL.
Example:Before join operation :
m =1->2->3->4->5->null
n =6->7->8->9->nullAfter join operation :
6->7->8->9->1->2->3->4->5->null
& If lists are NULL : If the list n is empty and itself NULL, then joining and referencing would obviously create NULL pointer issue.
Explanation : According to Static Single Assignment
--> A variable cannot be used more than once in the LHS
--> A variable should be initialized atmost once.
Now looking at the given options
1. a ā code violates condition 1 as p1 is initialized again in this statement: p1 = u * v
2. c- code is not valid as q1 = p2 * c , q2 = p4 + q3 ā In these statements p2, p4, q3 are not initialized anywhere
3. d- code is invalid as q2 = p + q is incorrect without moving it to register
Therefore, option B is only correct option.