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Operating System MCQ - Memory Management

6 In real-time operating systems, which of the following is the most suitable scheduling scheme?

7 Dirty bit is used to show the

8 If there are 32 segments, each of size 1 K byte, then the logical address should have

To specify a particular segment, 5 bits are required (since 2⁵ = 32). . Having selected a page, to select a particular byte one needs 10 bits (since 2¹⁰ = 1 k byte). So, totally 5 + 10 =15 bits are needed.

9 The first-fit, best-fit and the worst-fit algorithm can be used for

10 Consider a computer with 8 Mbytes of main memory and a 128 K cache. The cache block size is 4 K. It uses a direct mapping scheme for cache management. How many different main memory blocks can map onto a given physical cache block ?

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Question:

Consider a logical address space of 8 pages of 1024 words mapped into memory of 32 frames. How many bits are there in the logical address?

A. 9 bits
B. 11 bits
C. 13 bits
D. 15 bits

Correct answer: C

Explanation:

Logical address will have 3 bits to specify the page number (for 8 pages). 10 bits to specify the offset into each page (210 = 1024 words) =…

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