CTET Maths MCQ - Percentage

11 A trader buys a certain amount of goods worth Rs.22520. He decides to make a profit of 5.36% on the sale of goods worth Rs.5000 and increase the profit percent by 3.14% for sales upto 215000 and then increase the profit percent for the sale of remaining lot such that he is able to make a profit of 25% on the sale of the full lot. Then profit that he makes on the third lot of goods is

C.P. of goods for the trader = Rs.22520
S.P. = 125 x 22520 = Rs.28150
∴ Profit = Rs.5630
Now, 5630 = 0.0536 x 5000 + 0.085 x 10000 + (x/100)* 7520
=>5630 =268 - 850 + 75.2x
=>75.2x = Rs.4512, which is nothing but profit from sale of third lot.

12 Buy two and get one free. Which of the following is true?

Profit or loss of the sale depends upon how much profit the person is earning on the sale of two articles. If SP > CP of 1 article, there is a profit. If SP < CP of 1 article, there is a loss. If SP = CP of 1 article, there is not profit no loss. Thus, only (c) is true.

13 One merchant correctly calculates his percentage profit on the cost price; another wrongly calculates it on the selling price. The difference in actual profits if both claim to make 17 .5 % profit on goods sold at Rs.3760 is

CP of the merchant who calculates his % profit on CP = (3760/1.175) =Rs.3200
His profit = 0.175 x 3760 = Rs.560
Profit of the merchant who calculates his % profit on SP = 0.175 x 3760 = Rs.658
Difference in profit = 658 - 560 =Rs.98.

14 A trader allows a discount of 5 percent to his customers. What price should he mark on a article the cost price of which is Rs. 800 so as to make clear profit of 25 percent on his outlay?

Selling price = 800 x 1.25 =Rs. 1000

∴ Marked price = (1000/0.95) =1053 Rs.

15 A sports goods shop owner has 6 packets of balls each containing the same number of balls. If he sells each ball at Rs. 8 he gains Rs.96. If there were 1 ball less in each packet and he sells each ball at Rs.9 then he gains Rs.90 in the transaction. The cost price of each packet of balls is

Let there be n number of balls in each packet.
∴ 6n x 8 = CP + 96
⇒48n = CP + 96 ------------ (i)
Also, 6 (n - 1) x 9 = CP + 90
⇒54n - 54 = CP + 90
54n = CP + 144 ------------(ii)
Solving equations (i) and (ii),
we get, n = 8
∴ CP = 48 x 8 96 = 384 - 96 = Rs.288
Each packet cost = Rs.48.

CTET Maths MCQ - Percentage

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