Primitive disk operating system (POS) manages its disk files in contiguous blocks. A file is saved to the first available space that is large enough to hold the file. Assume that a disk has only 10 contiguous blocks of available free space. Which of the following set of file operations Fa=1, Fb=3, Fc=5, Fd=6 can not be completed given the set of files and file sizes specified below
| A. | save (ƒa), save (ƒb), save (ƒd), delete (ƒd), save (ƒc) |
| B. | save (ƒc), save (ƒa), delete (ƒc), save (ƒd) |
| C. | save (ƒd), save (ƒb), delete (ƒd), save (ƒc) |
| D. | save (ƒb), save (ƒa), delete (ƒb), save (ƒd) |
Answer : B Explanation : Given Fa=1, Fb=3, Fc=5, Fd=6 Option (a) save (ƒa), save (ƒb), save (ƒd), delete (ƒd), save (ƒc) is possible as we can save 1,3,6 in 9 contiguous block and then delete ( fd) to get 6 contiguous space. After that we can save ( fc ) = 5 in remaining 7 blocks.. So option (a) is possible. Similarly we can execute Option (c) and option (d) where as option (b) is not possible nirav said: (6:25pm on Sunday 5th May 2013)
explain it
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Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
