int a =1 , b=2;
a=chg(b) ;
cout << a << b ;
If the function chg is coded as
int chg(int &x)
{
x = 10;
return ();
}
then Functions
| A. | it results in compile-time error |
| B. | it results in run time error |
| C. | it prints 112 |
| D. | it prints 111 0 |
Answer : D Explanation : Here the parameter passing mechanism is pass by reference. Any change done to the parameter will be reflected outside the function. So, the value of b, after the exit of the function will be 10. |
|
|
Option: A Explanation : Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. Explanation will come here. |
