Quantitative Aptitude - Numbers and Algebra

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16. Sum of three prime numbers is 100. If one of them exceeds another by 36, then one of the numbers is

  • Option : D
  • Explanation : x + (x + 36) + y = 100
    ⇒2x + y = 64
    Therefore y must be even prime which is 2 
    2x + 2 = 64
    ⇒x = 31.
    ∴ Third prime number = x + 36 = 31+ 36 = 67
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17. A school has 5 divisions in a class IX having 60, 50, 55, 62 and 58 students. Mean marks obtained in a History test were 56, 64, 72, 63 and 50 by each division respectively. What is overall average of the marks per students?

  • Option : D
  • Explanation : Average = (60x56+50x64+55x72+62x63+58x50)/ (60+50+55+60+58 ) = (3360+3200+3960+3906+2900)/285 = 60.8
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18. What is the smallest number which when increased by 3 is divisible by 27, 35, 25 and 21?

  • Option : A
  • Explanation : L.C.M. of 27, 35, 25 and 21 = 4725

    ∴ Number = 4725-3 = 4722.

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19. Which of the following is true?

  • Option : B
  • Explanation :

    (A) Four consecutive even numbers can be written as 2n, 2n + 2, 2n + 4 and 2n + 6,where n is any natural number.
    Sum = 2n +(2n + 2) + (2n + 4) + (2n +6) = 8n + 12
    = 4(2n + 3) not always divisible by 8.
    Thus, (A) is not true.
    (B) Four consecutive odd numbers can be written as 2n-1, 2n+ 1, 2n + 3, 2n + 5 where n is a natural number
    Sum = (2n-1) + (2n + 1) + (2n + 3) + (2n + 5)
    = 8n + 8 = 8(n + 1) divisible by 8
    Thus, (B) is true
    (C) In product of n consecutive natural numbers atleast one is divisible by n, atleast one by n - 1 ... till 1.
    Thus product is atleast divisible by
    n * (n - 1) * (n - 2) *1  =  n!.
    Thus, (C) is not true.
    (D) Take four consecutive odd numbers as 7 x 9 x 11 x 13 which is not divisible by 15.
    Thus, (D) is not true.

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20. Sum of all odd numbers up to 100 is

  • Option : B
  • Explanation : Given numbers are 1, 3, 5.....99.
    This is an A.P with a = 1, d = 2
    Let it contain n terms
    ∴ 1 +(n-1)2 = 99
    => n = 50
    Hence required sum = n/2 (first term +last term)
    = 50/2(1 + 99) = 2500
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