Programming in C - Decision Making and Looping

Avatto > > UGC NET COMPUTER SCIENCE > > PRACTICE QUESTIONS > > Programming Languages and Computer Graphics > > Programming in C > > Decision Making and Looping

21. The following program fragment
int i = 5;
do
{
putchar(i + 100);
printf("%d", i--);
}
while (i);
results in the printing of

Answer
Comment
Array

Option : A
Explanation :
putchar (1 0 5) will print the ASCII equivalent of 105 i.e.. ' i '. The printf statement prints the current value of i. i.e. 5 and then decrements it. So, h4 will be printed in the next pass. This continues until ' i ' becomes 0, at which point the loop gets terminated.

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22. The following loop
while(printf("%d", printf("az")))
printf("by");

Answer
Comment
Array

Option : D
Explanation :
printf("az") prints az and returns a value 2 (since it printed two characters). So. the condition results in the printing of az2. Since it always returns 2, it is an infinite loop. The output will be az2byaz2by...

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23. The following statements
for (i= 3; i < 15; i += 3)
{
printf ("%d ", I);
++i;
}
will result in the printing of

Answer
Comment
Array

Option : C
Explanation :

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24. In a for loop, if the condition is missing, then,

Answer
Comment
Array

Option : B
Explanation :

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25. In a for loop, if the condition is missing, then infinite looping can be avoided by a

Answer
Comment
Array

Option : D
Explanation :

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Decision Making and Looping

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