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Programming in C MCQ - Find the Output

11 Find the output of the following C code (assume #include and that the code is inside int main(void)):

int marks = 85;

if (marks >= 40)
    printf("Pass");
else if (marks >= 75)
    printf("Distinction");
else
    printf("Fail");

An else-if ladder executes only the first true branch. marks >= 40 is true, so Pass is printed and the later test is skipped.

12 Find the output of the following C code (assume #include and that the code is inside int main(void)):

int n = 15;

if (n < 10)
    printf("A");
else if (n < 20)
    printf("B");
else if (n < 30)
    printf("C");
else
    printf("D");

15 < 10 is false, but 15 < 20 is true. Therefore B is printed and later branches are skipped.

13 Find the output of the following C code (assume #include and that the code is inside int main(void)):

int x = 20;

if (x > 20)
    printf("A");
else if (x >= 20)
    printf("B");
else if (x == 20)
    printf("C");
else
    printf("D");

x > 20 is false, while x >= 20 is true. The ladder prints B without testing the later x == 20 branch.

14 Find the output of the following C code (assume #include and that the code is inside int main(void)):

int x = 7;

if (x > 5)
    printf("A");
else if (x > 3)
    printf("B");

if (x < 10)
    printf("C");
else
    printf("D");

The first ladder prints A. The second independent if statement also succeeds and prints C, giving AC.

15 Find the output of the following C code (assume #include and that the code is inside int main(void)):

int a = 5, b = 10;

if (a > 0 || ++b > 10)
    printf("%d", b);
else
    printf("NO");

Because a > 0 is true, logical OR short-circuits and ++b is not evaluated. b remains 10.

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Question:

Find the output of the following C code (assume #include <stdio.h> and that the code is inside int main(void)):int i, j, sum = 0; for (i = 1;…

A. 24
B. 30
C. 32
D. 40

Correct answer: C

Explanation:

Only odd i+j pairs contribute: 6 for i=1, 8 for i=2, and 18 for i=3, totaling 32.

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Question

Find the output of the following C code (assume #include <stdio.h> and that the code is inside int main(void)):

int i, j, sum = 0;
for (i = 1; i <= 3; i++) {
    for (j = 1; j <= 4; j++) {
        if ((i + j) % 2 == 0)
            continue;
        sum += i * j;
    }
}
printf("%d", sum);

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