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Database MCQ - Normalization for Relational Databases

Correct AnswerOption B
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empdt1 {empcode, name, street, city, state, pincode)
Given functional dependency
pincode -> (city) (state)
(street) (city) (state) -->pincode
This is in I NF and 2NF but not in 3NF because it contains transitive dependency.
Hence the correct answer is (b).
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Correct AnswerOption A
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Primary key (candidates key) for this relation is [F1] [F2] because [F1, F2] column contains [F1, F2, F3, F4, F5]
So, there is, functional dependency F1 -> F3, F2
It also has partial dependency so it is not in 2nd, 3rd NF.
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Correct AnswerOption D
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Correct AnswerOption B
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Follow:
CD—>A {CD —>E;E —> A; E —>C}
CD —> C
BC —> CD
B—>D;
CD—>E;
E—>A;
A—>C
AC—>BC:
A—>B:
A—>C
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Correct AnswerOption D
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