PREVIOUS YEAR SOLVED PAPERS - JULY 2016 Paper 2

6. Which of the following logic expressions is incorrect?

  • Option : C
  • Explanation :
    We know that x ⊕ y = x`y + xy` So,
    1. 1 ⊕ 0 = 1`0 + 10` = 0 * 0 + 1 * 1 = 0 + 1 = 1
    2. 1 ⊕ 1 ⊕ 1 = (1 ⊕ 1) ⊕ 1 = (1`1 + 11`) ⊕ 1 = (0) ⊕ 1 = 1`0 + 10` = 0 * 0 + 1 * 1 = 0 + 1 = 1
    3. 1 ⊕ 1 ⊕ 0 = 1 ⊕ (1 ⊕ 0 ) = 1 ⊕ ( 1`0 + 10` = 0 * 0 + 1 * 1 = 0 + 1 ) = 1 ⊕ 1 = 1`1 + 11` = 0
    4. 1 ⊕ 1 = 1`1 + 11` = 0
    So, option (C) is correct.
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7. The IEEE-754 double-precision format to represent floating point numbers, has a length of _____ bits.

  • Option : D
  • Explanation :
    The IEEE-754 double-precision format to represent floating point numbers, has a length of 64 bits. 1 bit for sign, 11 bit for exponent and rest 52 is for fraction. So, option (D) is correct.
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8. Simplified Boolean equation for the following truth table is: 

xyzF
0000
0011
0100
0111
1001
1010
1101
1110

  • Option : C
  • Explanation :

    So, option (C) is correct.
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9. The simplified form of a Boolean equation(­­­­­­­­AB­'+AB­'C+AC) (A­'C­'+B­') is :

  • Option : A
  • Explanation :
    (AB` + AB`C + AC) (A`C` + B`) = AB` +AB`C +AB`C = AB` +AB`C = AB`(1 + C) = AB` So, option (A) is correct.
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10. In a positive-edge-triggered JK flip-flop, if J and K both are high then the output will be _____ on the rising edge of the clock.

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Related Quiz.
JULY 2016 Paper 2