uptetd16p1 q94
0. The sum of three consecutive multiples of 3 is 99. These multiples are
- Option : C
- Explanation : (C) Let the three consecutive multiples of 3 be 3x, 3x + 3, 3x + 6
Then, according to the question,
3x + 3x + 3 + 3x + 6 = 99
⇒ 9x + 9 = 99
⇒ 9(x + 1) = 99
⇒ x + 1 = 11
⇒ x = 11 - 1 = 10
Thus, the three multiples are
3x = 3 × 10 = 30
3x + 3 = 3 × 10 + 3 = 33
3x + 6 = 3 × 10 + 6 = 36
Multiples of 3 are 30, 33, 36.
