UPTET Feb 2014, q122
0. If (x - 2) is a factor of x3 + ax2 + bx + 16 and b = 4a, then respective values of a and b are
- Option : C
- Explanation : Let f (x) = x3 + ax2 + bx + 16
Since, (x - 2) is a factor of f (x)
∴ f (2) = 0
i.e. 8 + 4a + 2b + 16 = 0
⇒ 8 + 4a + 8a + 16 = 0 [as b = 4a]
∴ a = -2
and b = 4a-8
⇒ b=4(-2)=-8
⇒ a = -2, b = -8.
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