Time and Distance Q.14

14A person travelled a distance of 610 km in 9 hours. He travelled the first phase at a speed of 40 kmph and the rest at 90 kmph. The distance travelled during the first phase is

Option : C
Explanation : Let the distance travelled in first phase be x km.
Then, distance travelled in second phase = (610 − x) km.
Hence, x/40 + (610 − x)/90 = 9 hours
⇒ x = 160 km

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