Memory Hierarchy Q.26

26If each address space represents one byte of storage space, how many address lines are needed to access RAM chips arranged in a 4 x 6 array, where each chip is 8K x 4 bits

Option : D
Explanation : As there are 4*6 = 24 chips so (as 2⁵>= 24 ) 5 bits are required to address them.
in each RAM number of bytes=(8k*4)/8 = 4k
So to represent 4k we need(as 2¹²=4096) 12 bits
Therefore to represent total structure we need 12+5=17 bits.

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