Gate2019 cs Q42

  • Option : C
  • Explanation :
    X(PQRS) {QR → S, R → P, S → Q} decomposed into
     Y(PR)Z(QRS)
     {R → P}{QR → S, S → Q}
     Candidate key : RCandidate key : QR, RS
     Relation Y in BCNFRelation Z in 3NF but not BCNF
    The common attribute between Y and Z relations is R which is key for relation Y.
    So that given decomposition is lossless join decomposition.
         R → P in Y
        
    and dependency preserving decomposition.
    Hence, C is the correct answer.
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