Explanation : X(PQRS) {QR → S, R → P, S → Q} decomposed into
Y(PR)
Z(QRS)
{R → P}
{QR → S, S → Q}
Candidate key : R
Candidate key : QR, RS
Relation Y in BCNF
Relation Z in 3NF but not BCNF
The common attribute between Y and Z relations is R which is key for relation Y.
So that given decomposition is lossless join decomposition.
R → P in Y
and dependency preserving decomposition.
Hence, C is the correct answer.